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badminton dimensions
i need help with an algebra word problem i need to solve for x,y i am having trouble setting up the problem?
the problem is: the perimeter of a badminton court is 128ft. after a game of badminton a player's coach estimates that the athlete has run a total of 444ft, which is equivalent to six time the courts length plus nine times it width. What are the dimensions of a standard badminton court
the answer is 44 by 20ft the problem im having is setting up the problem
perimeter is the sum of all 4 sides so twice the length + twice the width = 128 or L + W = 64 or L = 64 -W
From the next statement 6L + 9W = 444
substitute for L to get 6(64 - W ) + 9W = 444
384 -6W + 9W = 444
3W = 60 and W = 20
plug 20 in for W in L = 64 -W to get L = 44
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pls.furnish complete dimensions of a badminton court.?
Please go to the site below. It gives the complete dimension including the service lines, etc.
Have fun playing.